[HackerRank] MySQL - Top Competitors

select h.hacker_id, h.name
from submissions as s
    join hackers as h on s.hacker_id = h.hacker_id
    join challenges as c on s.challenge_id = c.challenge_id
    join difficulty as d on c.difficulty_level = d.difficulty_level
where d.score = s.score
group by h.hacker_id, h.name
having count(s.hacker_id) > 1
order by count(s.hacker_id) desc, s.hacker_id asc